Conceptly
LessonsFormulasPricing
Sign inStart free
Conceptly
TermsPrivacyRefunds
© 2026 · Physics for everyone
  1. Home
  2. Lessons
  3. Mechanics
  4. Banked Curves
All lessons Mechanics24 min

Banked Curves

Complete each stage to unlock the next one.

← Circular MotionUniversal Gravitation →
01
Hook
02
Explore
03
Formalize
04
Practice
05
Challenge
Interactive simulation
01

Hook

A car takes a flat corner and relies entirely on friction to keep from sliding out. But race tracks, velodromes, and highway off-ramps tilt their corners inward. On a perfectly banked curve a car could round the bend on sheet ice — with zero friction. How can tilting the road replace friction?

02

Explore

Complete previous stage
03

Formalize

Complete previous stage
04

Practice

Complete previous stage
05

Challenge

Complete previous stage
Spoilers

Banked Curves — summary and key formula

ShowHide

The question

A car takes a flat corner and relies entirely on friction to keep from sliding out. But race tracks, velodromes, and highway off-ramps tilt their corners inward. On a perfectly banked curve a car could round the bend on sheet ice — with zero friction. How can tilting the road replace friction?

On a flat curve, the only thing pulling a car into the turn is sideways friction; lose grip and you slide off. Banking the road tilts the normal force so that its horizontal component points toward the centre of the circle and supplies the centripetal force by itself. For one special 'design speed' the banking angle does the whole job and no friction is needed. Above or below that speed, friction makes up the difference — until even friction runs out.

The key idea

On a banked curve the normal force is tilted so part of it points toward the circle's centre. At the frictionless 'design speed' the banking angle alone supplies the centripetal force, giving a clean relation between angle, speed, and radius.

Set up two force equations for a car on a frictionless banked road. Perpendicular to the centre (vertical): N cos θ = mg. Toward the centre (horizontal): Nsinθ=mv2/rN sin \theta = mv^2/rNsinθ=mv2/r. Dividing the second by the first cancels N and m: tanθ=v2/(rg)tan \theta = v^2/(rg)tanθ=v2/(rg). Solving for speed gives the design speed v = √(rg tan θ). If the car goes faster than this, it tends to slide up and outward, so friction must act down the incline; if slower, it tends to slip down and inward, so friction acts up the incline. The banking angle is chosen for the most common speed so that wear and skidding are minimised. **Limiting case:** θ→0\theta \to 0θ→0 leaves friction to do everything (vmax=μgrv_{max} = \sqrt{\mu g r}vmax​=μgr​, the flat-road formula); at the design speed v=grtan⁡θv = \sqrt{gr\tan\theta}v=grtanθ​ the normal force alone supplies the turn and friction is not needed at all. **Connect it:** nothing new is happening — it is the same mv2/rmv^2/rmv2/r as ordinary circular motion; banking simply tilts NNN so a slice of it points at the centre.

The formula

tan⁡θ=v2rgvdesign=rgtan⁡θ\tan\theta = \frac{v^2}{rg} \qquad v_{\text{design}} = \sqrt{rg\tan\theta}tanθ=rgv2​vdesign​=rgtanθ​
  • ·θ = banking angle from horizontal
  • ·v = design speed
  • ·r = radius of the curve
  • ·g = 9.8 m/s². No mass and no friction coefficient appear at the design speed.

Common mistake

Thinking a banked curve removes the need for friction at any speed — the bank fully replaces friction only at one design speed; go faster or slower and you still rely on friction.